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Simplifying c2 + -3c + -180 = 0 Reorder the terms: -180 + -3c + c2 = 0 Solving -180 + -3c + c2 = 0 Solving for variable 'c'. Factor a trinomial. (-12 + -1c)(15 + -1c) = 0Subproblem 1
Set the factor '(-12 + -1c)' equal to zero and attempt to solve: Simplifying -12 + -1c = 0 Solving -12 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '12' to each side of the equation. -12 + 12 + -1c = 0 + 12 Combine like terms: -12 + 12 = 0 0 + -1c = 0 + 12 -1c = 0 + 12 Combine like terms: 0 + 12 = 12 -1c = 12 Divide each side by '-1'. c = -12 Simplifying c = -12Subproblem 2
Set the factor '(15 + -1c)' equal to zero and attempt to solve: Simplifying 15 + -1c = 0 Solving 15 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-15' to each side of the equation. 15 + -15 + -1c = 0 + -15 Combine like terms: 15 + -15 = 0 0 + -1c = 0 + -15 -1c = 0 + -15 Combine like terms: 0 + -15 = -15 -1c = -15 Divide each side by '-1'. c = 15 Simplifying c = 15Solution
c = {-12, 15}
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